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John Connor
Senior Member
Joined: 01.Feb.2011
Location: United States
Using: AutoCAD 2018
Status: Offline
Points: 7175
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Posted: 26.Apr.2012 at 13:01 |
I have no idea what "if not flat" means. If the height is given as "0" of course its flat! You're creating a spiral not a helix.
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"Humans have a strength that cannot be measured. This is John Connor. If you are reading this, you are the resistance."
<<AutoCAD 2015>>
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xrayrays
Groupie
Joined: 24.Apr.2012
Location: Philippines
Using: autocad2004, autocad2013
Status: Offline
Points: 26
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Posted: 26.Apr.2012 at 14:03 |
i think helix i need.
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Thanks,
Marcuel Gubaynon
Technical/Draftsman
Philippines
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philippe JOSEPH
Senior Member
Joined: 14.Mar.2011
Location: France
Using: AutoCAD Mechanical 2017
Status: Offline
Points: 1425
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Posted: 26.Apr.2012 at 14:37 |
Hello N° 3
If you are using HELIX in a 2D drawing, beware of not creating a 3D HELIX.
In the properties panel you've got access to 10 modifiable values.
Position X ........
Position Y .......
Position Z 0 ---> must be zero
Constrain your choise between 3
Height 0 ---> must be zero
Turns ---> your choise
Height of turns 0 ---> must be zero
Base radius ---> your choise
Top radius ---> your choise
XXXXX ( I don't know in english ) trigo or time direction
( excuse me for the terms in french to english )
Please let us know if it helped and if possible let us see your DWG, I'm interested.
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John Connor
Senior Member
Joined: 01.Feb.2011
Location: United States
Using: AutoCAD 2018
Status: Offline
Points: 7175
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Posted: 26.Apr.2012 at 14:43 |
You're drawing a 2D spiral which means there is NO height! Which is why I told you to use a value of "0".
A helix with a different radius for the base and the top will produce a spiral. If the radii for both is the same then you won't get the desired result.
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"Humans have a strength that cannot be measured. This is John Connor. If you are reading this, you are the resistance."
<<AutoCAD 2015>>
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John Connor
Senior Member
Joined: 01.Feb.2011
Location: United States
Using: AutoCAD 2018
Status: Offline
Points: 7175
|
Posted: 26.Apr.2012 at 14:44 |
This is what you are looking to achieve right?
http://en.wikipedia.org/wiki/File:Archimedean_spiral.svg
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"Humans have a strength that cannot be measured. This is John Connor. If you are reading this, you are the resistance."
<<AutoCAD 2015>>
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xrayrays
Groupie
Joined: 24.Apr.2012
Location: Philippines
Using: autocad2004, autocad2013
Status: Offline
Points: 26
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Posted: 26.Apr.2012 at 14:51 |
i only have center point: number of rotations: Growth per rotations: Points per rotation <30>:
thats the command in my spiral.slp
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Thanks,
Marcuel Gubaynon
Technical/Draftsman
Philippines
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John Connor
Senior Member
Joined: 01.Feb.2011
Location: United States
Using: AutoCAD 2018
Status: Offline
Points: 7175
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Posted: 26.Apr.2012 at 15:21 |
Guess what? That is not going to give you what you want.
What is your base radius? What is your top radius? How many turns do you want?
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"Humans have a strength that cannot be measured. This is John Connor. If you are reading this, you are the resistance."
<<AutoCAD 2015>>
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xrayrays
Groupie
Joined: 24.Apr.2012
Location: Philippines
Using: autocad2004, autocad2013
Status: Offline
Points: 26
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Posted: 26.Apr.2012 at 15:37 |
I Enter this
center point number of rotations:5 Growth per rotations: 10 Points per rotation <30>: 90
its flat spiral.
hmp, how do i fix to not flat.
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Thanks,
Marcuel Gubaynon
Technical/Draftsman
Philippines
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John Connor
Senior Member
Joined: 01.Feb.2011
Location: United States
Using: AutoCAD 2018
Status: Offline
Points: 7175
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Posted: 26.Apr.2012 at 15:40 |
You have a habit of not answering questions put directly to you. I did NOT ask what spiral.lsp was requesting for input.
Please answer MY questions.
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"Humans have a strength that cannot be measured. This is John Connor. If you are reading this, you are the resistance."
<<AutoCAD 2015>>
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