So i need to draw a line at a 0.50% slope. Never drawn that way before. Whats the command for that??

Maybe this will help.http://www.engineeringtoolbox.com/slope-degrees-gradient-grade-d_1562.htmlOnce you know the number of degrees you can use direct distance entry at the command line.Example: @7.5<45This would be read as 7.5 units long at an angle of 45 degrees.


John Connor2012-01-12 16:59:07

to obtain 50% slope, you first need to know the length of the line, then multiply this by .5 and you will have the difference in length in the Y axis between the origin point of your line and the end point of this to have a 50 % slope, to find the angle, use the inverse tangent function. I hope this helps.

0.5% = 0.5/100 = 0.005.  Think rise over run.  In this case for every unit of run there will be a rise of 0.005 units.  You don't need to know the length of the line to set this slope.  You can just set up an angled construction line thru the origin using this as a guide and draw a line on it at any length you like.Dave

Erroneously indicate 50% instead of 0.5%, if one line is a must have this slope, the procedure may be  Dave also, but if you need draw an entire plane try UCS command and adjust the angle in the X axis for the slope you need, and finally returns back to X axis at 0