Hi, I need to use it and must use a dimension template that already exists . This is with a scale factor of " 0.2 " , if I type "5" it shows your text to "1" , but its size in the model still 5.I want to use a linear dimension (apply to a normal line) that I type "0,5" but the size in the automaticaly multiply yo "2,5". Are there a command to do that (prefer whithout change the dimension style)? Thank you, sorry the bad english.

Since you do not want to create a different dimension style wouldn't you have to override the dimension using Quick Properties or in the Properties palette?

Too slow, I have more then 1000 of dimensions to draw. And if I draw the dimensions in the size I need to be, and scale 0.2 to become the size that need to be in the model, It won`t reference to the green line (floor)I want to click the gren line, make a perpendicular (just ortho is fine), and type 1.5, the dimensions/line will have a size of 7.5 (factor scale 0.2), i don`t care if i need to type some command before. Thats my ideia, maybe someone have a better. If there is no way, how I do that editing the dimension style?

I don't understand how people get into these types of situations.Have you tried using the Scale Factor on the Primary Units tab?
John Connor2015-07-29 18:22:04

Since this is clearly for vertical-exaggeration application, I will assume that they are always and only vertical dimensions.  If you always dimension them downward, try something like this [in simplest terms, and untested]:(defun C:DVE (/ pt actual); = Dimension with Vertical Exaggeration  (setvar 'dimstyle "YourVerticalExaggerationDimensionStyleName")  (setq    pt (getpoint "\nTop-end Dimension definition point: ")    actual (getdist "\nTrue vertical distance downward: ")  ); setq  (command "_.dimlinear" pt (polar pt (* pi 1.5) (* actual 5)) "@")); defunIf you might sometimes want to do them from bottom upward, adjustments would be needed.  And it could use the usual controls and enhancements, but see whether it works for you.