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  <title>CAD Forum discussion (EN) : modeling a mathematical shape</title>
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   <title><![CDATA[modeling a mathematical shape : Another, (polar)-based, solution...]]></title>
   <link>https://www.cadforum.cz/forum_en/forum_posts.asp?TID=12217&amp;PID=34327&amp;title=modeling-a-mathematical-shape#34327</link>
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    <![CDATA[<strong>Author:</strong> <a href="https://www.cadforum.cz/forum_en/member_profile.asp?PF=353260">Kent Cooper</a><br /><strong>Subject:</strong> 12217<br /><strong>Posted:</strong> 17.Feb.2017 at 20:56<br /><br />Another, (polar)-based, solution (along with Vladimir's solution above) is over <a href="http://https://forums.autodesk.com/t5/autocad-2013-2014-2015-2016-2017/modeling-a-mathematical-shape/m-p/6886507#M163554" target="_blank" rel="nofollow">here</a>.&nbsp;See also other Posts in that same thread.<div><br></div><div>EDIT: &nbsp;That link doesn't seem to work. &nbsp;Try copy/pasting this:</div><div><br></div><div>https://forums.autodesk.com/t5/autocad-2013-2014-2015-2016-2017/modeling-a-mathematical-shape/m-p/6886507#M163554</div><span style="font-size:10px"><br /><br />Edited by Kent Cooper - 17.Feb.2017 at 21:02</span>]]>
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   <pubDate>Fri, 17 Feb 2017 20:56:50 +0000</pubDate>
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   <title><![CDATA[modeling a mathematical shape :  You can use our 2DPLOT utility...]]></title>
   <link>https://www.cadforum.cz/forum_en/forum_posts.asp?TID=12217&amp;PID=34325&amp;title=modeling-a-mathematical-shape#34325</link>
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    <![CDATA[<strong>Author:</strong> <a href="https://www.cadforum.cz/forum_en/member_profile.asp?PF=3">Vladimir Michl</a><br /><strong>Subject:</strong> 12217<br /><strong>Posted:</strong> 17.Feb.2017 at 08:34<br /><br />You can use our 2DPLOT utility (see <a href="http://www.cadstudio.cz/en/apps/2dplot/" target="_blank" rel="nofollow">http://www.cadstudio.cz/en/apps/2dplot/</a>). You equation then should be expressed in cartesian space (X/Y):<div>&nbsp;</div><div>; for range (0-1.5&gt;<br>(defun fPolar1 (u / r tau alfa R0)<br>;x = (* r (cos th))<br>;y = (* r (sin th))<br>&nbsp;(setq r u)<br>&nbsp;(setq tau 1.1) ; example<br>&nbsp;(setq alfa 1.0) ; example<br>&nbsp;(setq R0 0.1) ; example<br>&nbsp;(setq th (* alfa (sin (/ (* pi (log (/ r R0))) (log tau))))) ; your expression<br>&nbsp;(list (* r (cos th)) (* r (sin th))) ; return (X Y)<br>)<br></div><div>Then call:</div><div>&nbsp;</div><div>(2Dplot fPolar1 0.001 1.5 0.001)</div><div>&nbsp;</div><div>meaning - draw my function "fPolar1" from 0.001 to 1.5 (the radius), with ministeps of 0.001</div><div>&nbsp;</div>]]>
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   <pubDate>Fri, 17 Feb 2017 08:34:02 +0000</pubDate>
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   <title><![CDATA[modeling a mathematical shape :  The equations would be necessary....That...]]></title>
   <link>https://www.cadforum.cz/forum_en/forum_posts.asp?TID=12217&amp;PID=34321&amp;title=modeling-a-mathematical-shape#34321</link>
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    <![CDATA[<strong>Author:</strong> <a href="https://www.cadforum.cz/forum_en/member_profile.asp?PF=353260">Kent Cooper</a><br /><strong>Subject:</strong> 12217<br /><strong>Posted:</strong> 15.Feb.2017 at 22:13<br /><br />The equations would be necessary....<div>&nbsp;</div><div>That looks like some kind &#091;two kinds, really&#093; of formula in which the angle to a point on the curve is based on the inverse of a trigonometric function whose value swings between positive and negative without ever going to infinity &#091;such as sine or cosine&#093;, applied to some&nbsp;multiplier of the local radius, and for the browner curve with a constant angle &#091;looks like 45 degrees&#093; added to the result.&nbsp; That shouldn't be very hard to work out -- for a related routine that draws <em>polynomial</em> functions &#091;y = ax^n + bx^(n-1) + .... + px^2 + qx + r&#093;, see my PolynomialFunction.lsp routine, available <a href="http://cadtips.cadalyst.com/lisp-code-modules/draw-polynomial-functions" target="_blank" rel="nofollow">here</a>.&nbsp; But this one, being radial,&nbsp;would not involve X and Y coordinates, but&nbsp;instead&nbsp;(polar) functions measured from the origin as basepoint,&nbsp;in a (repeat) function stepping through small increments of radius as the distance arguments, and calculating the angle arguments for each based on the equation,&nbsp;and presumably used in&nbsp;a SPLINE, or perhaps a POLYLINE that you could spline-curve to smooth it out.</div>]]>
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   <pubDate>Wed, 15 Feb 2017 22:13:06 +0000</pubDate>
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   <title><![CDATA[modeling a mathematical shape : how can i model such a plot in...]]></title>
   <link>https://www.cadforum.cz/forum_en/forum_posts.asp?TID=12217&amp;PID=34319&amp;title=modeling-a-mathematical-shape#34319</link>
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    <![CDATA[<strong>Author:</strong> <a href="https://www.cadforum.cz/forum_en/member_profile.asp?PF=707415">Frank98</a><br /><strong>Subject:</strong> 12217<br /><strong>Posted:</strong> 15.Feb.2017 at 21:28<br /><br />how can i model such a plot in autocad.<div>this plot what created using a mathematical formula ,demostrated in mathlab.</div><div>thanks<br><br><img src="uploads/707415/Capture2.JPG" height="560" width="576" border="0" /></div>]]>
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   <pubDate>Wed, 15 Feb 2017 21:28:26 +0000</pubDate>
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